[akhaldi] 64710: [CRT] * Update MSVCRT_I10_OUTPUT(). CORE-8540

Author: akhaldi
Date: Mon Oct 13 10:31:36 2014
New Revision: 64710

URL: http://svn.reactos.org/svn/reactos?rev=64710&view=rev
Log:
[CRT]
* Update MSVCRT_I10_OUTPUT().
CORE-8540

Modified:
    trunk/reactos/lib/sdk/crt/misc/i10output.c

Modified: trunk/reactos/lib/sdk/crt/misc/i10output.c
URL:
http://svn.reactos.org/svn/reactos/trunk/reactos/lib/sdk/crt/misc/i10output…
==============================================================================
--- trunk/reactos/lib/sdk/crt/misc/i10output.c	[iso-8859-1] (original)
+++ trunk/reactos/lib/sdk/crt/misc/i10output.c	[iso-8859-1] Mon Oct 13 10:31:36 2014
@@ -11,7 +11,7 @@
 
 /*********************************************************************
  *              $I10_OUTPUT (MSVCRT.@)
- * ld - long double to be printed to data
+ * ld80 - long double (Intel 80 bit FP in 12 bytes) to be printed to data
  * prec - precision of part, we're interested in
  * flag - 0 for first prec digits, 1 for fractional part
  * data - data to be populated
@@ -24,16 +24,22 @@
  *      Native sets last byte of data->str to '0' or '9', I don't
know what
  *      it means. Current implementation sets it always to '0'.
  */
-int CDECL MSVCRT_I10_OUTPUT(long double ld, int prec, int flag, struct _I10_OUTPUT_DATA
*data)
+int CDECL MSVCRT_I10_OUTPUT(_LDOUBLE ld80, int prec, int flag, struct _I10_OUTPUT_DATA
*data)
 {
     static const char inf_str[] = "1#INF";
     static const char nan_str[] = "1#QNAN";
 
-    double d = ld;
+    /* MS' long double type wants 12 bytes for Intel's 80 bit FP format.
+     * Some UNIX have sizeof(long double) == 16, yet only 80 bit are used.
+     * Assume long double uses 80 bit FP, never seen 128 bit FP. */
+    long double ld = 0;
+    double d;
     char format[8];
     char buf[I10_OUTPUT_MAX_PREC+9]; /* 9 = strlen("0.e+0000") + '\0'
*/
     char *p;
 
+    memcpy(&ld, &ld80, 10);
+    d = ld;
     TRACE("(%lf %d %x %p)\n", d, prec, flag, data);
 
     if(d<0) {
@@ -59,7 +65,7 @@
     }
 
     if(flag&1) {
-        int exp = (int)(1+floor(log10(d)));
+        int exp = 1+floor(log10(d));
 
         prec += exp;
         if(exp < 0)
@@ -83,7 +89,7 @@
         data->pos++;
 
     for(p = buf+prec+1; p>buf+1 && *p=='0'; p--);
-    data->len = (BYTE)(p - buf);
+    data->len = p-buf;
 
     memcpy(data->str, buf+1, data->len);
     data->str[data->len] = '\0';